And if I substitute in that value for omega and
this value for L, I will get 103.7 j.
And similarly, I can solve for
Z sub C, that's 1 over j omega C.
And with this value of omega,
that value of C, I get -318.3 j.
Okay, so that's step one.
Step two is to solve this using standard methods.
Now, I'm interested, in particular, this voltage right there.
So, if I want to do this voltage, then I can look at it in terms of trying
to do a voltage divider law here, but I have to first combine these two resistors.
So let's let Z sub 1 equal that combination.
Z sub L in parallel with R and
that would be Z sub L product over the sum.