And if I substitute in that value for omega and

this value for L, I will get 103.7 j.

And similarly, I can solve for

Z sub C, that's 1 over j omega C.

And with this value of omega,

that value of C, I get -318.3 j.

Okay, so that's step one.

Step two is to solve this using standard methods.

Now, I'm interested, in particular, this voltage right there.

So, if I want to do this voltage, then I can look at it in terms of trying

to do a voltage divider law here, but I have to first combine these two resistors.

So let's let Z sub 1 equal that combination.

Z sub L in parallel with R and

that would be Z sub L product over the sum.