And that will be equal to x squared over 0.0529- x.

Well this is a very small k, when you divide these two values,

you get a very small k.

So, we can assume that x will be negligible and can ignore that term.

And you might want to stop the video and solve for x.

When you do, you should obtain that x is 5.6 times 10 to the minus 4.

And that is small so it's a legitimate assumption that we made and

then we can obtain the pH from there.

pH would be the negative log of this number.

So you take the negative log of that value,

you will obtain the value of 3.25 and that's the pH.

Add the equivalent to point between a weak base and a strong acid.

So we gotta consider, before we finish, is this a good pH, is it a reasonable pH?

Well, any time you're doing a titration where the acid is strong, but

the acid is weak, it's going to have a pH at the equivalence point less than seven.

So that is a legitimate value that we have obtained here for this problem.