So that is the next step, we have our data table
now I need to set up our k expression.
So k is going to equal to NO squared because I have NO as a product. now I need to set up our k expression.
So k is going to equal to NO squared because I have NO as a product.
2 is the coefficient of it, so that becomes the power.
N_2 is an reactant 2 is the coefficient of it, so that becomes the power.
N_2 is an reactant
and O_2 is a reactant so they both go into the denominator.
They both have coefficients of 1
so I do not have any powers associated with them.
Now, I have k equals NO squared
over N_2 times O_2
I can plug in the values I know over N_2 times O_2
I can plug in the values I know
and I find that I get 4.10 x 10 ^ -4
equals 2x squared
because I had 2x in my equilibrium row
I still have to remember to square that
because 2x represents the concentration.
The square is part of the law of mass action.
On the bottom, I have 0.250 - x The square is part of the law of mass action.
On the bottom, I have 0.250 - x
and 0.430 - x.
Now if I were to solve this
and rearrange to solve time for x
what I am going to find, is that I have a quadratic equation.
This makes the calculation a little more complicated. what I am going to find, is that I have a quadratic equation.
This makes the calculation a little more complicated.
However, in some cases
we can make a simplifying assumption.